If the measure of the interior angle of a regular polygon is 60° greater than the measure of its exterior angle then how many sides does it have?
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let the exterior angle be x
so interior angle will be x+60
the aim of both the angles interior and exterior will be 180
so x+(x+60)=180
2x=180-60
2x=120
x=60
to find out sides in a regular polygon which has exterior angle 60°will be
360°(as the sum of the exterior angles )/60°=6 sides
pls mark as BRAINLIEST
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