If the measure of three interior angles of a triangle are in the ratio 3: 4: 5, then
the measure of the smallest angle of the triangle is?
Answers
Answered by
1
Answer:
Answer:
1st angle = 60°
2nd angle = 80°
3rd angle =100°
4th angle = 120°
Step-by-step explanation:
In a quadrilateral ABCD, the angles are in ratio 6:8:10:12.
Let the angles of the quadrilateral be 6x , 8x , 10x and 12x respectively.
We know that,
The sum of the interior angles of a quadrilateral are equal to 360°.
Then,
\implies⟹ 6x+8x+10x+12x=360°
\implies⟹ 36x = 360°
\implies⟹ x=360°/36
\implies⟹ x = 10°
Therefore,
The 4 angles,
1st angle = 6×10 = 60°
2nd angle = 8×10 = 80°
3rd angle = 10×10= 100°
4th angle = 12×10 = 120°
____________________
Answered by
1
Answer:
Let the numbers in the ratio be x , so the angles are 3x,4x and 5x
A.T.Q,
3x+4x+5x=180°(Angle sum property)
12x=180°
x=180/12
x=15°
and the smallest angle will ne 3x=3×15°=45°
So,the smallest angle=45°
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