Math, asked by hritiksingh609, 3 months ago

If the measure of three interior angles of a triangle are in the ratio 3: 4: 5, then
the measure of the smallest angle of the triangle is?

Answers

Answered by kartikenterprises99
1

Answer:

Answer:

1st angle = 60°

2nd angle = 80°

3rd angle =100°

4th angle = 120°

Step-by-step explanation:

In a quadrilateral ABCD, the angles are in ratio 6:8:10:12.

Let the angles of the quadrilateral be 6x , 8x , 10x and 12x respectively.

We know that,

The sum of the interior angles of a quadrilateral are equal to 360°.

Then,

\implies⟹ 6x+8x+10x+12x=360°

\implies⟹ 36x = 360°

\implies⟹ x=360°/36

\implies⟹ x = 10°

Therefore,

The 4 angles,

1st angle = 6×10 = 60°

2nd angle = 8×10 = 80°

3rd angle = 10×10= 100°

4th angle = 12×10 = 120°

____________________

Answered by Sakhtlounda2503
1

Answer:

Let the numbers in the ratio be x , so the angles are 3x,4x and 5x

A.T.Q,

3x+4x+5x=180°(Angle sum property)

12x=180°

x=180/12

x=15°

and the smallest angle will ne 3x=3×15°=45°

So,the smallest angle=45°

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