if the measurements of side of a e are pointy p (-5,6)
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P divides of the line AB=2:3
Q divides of line AB=3:4
The distance between P and Q=2 cm
we have to find the length of AB=?
AB=AP+PB=2x+3x=5x
Or
AB=AQ+QB=3x+4x=7x
LCM of 5x and 7x=35x=AB
AP+PQ=AQ
2x+2=3x
x=2,
The length of AB=35×2 cm=70 cm
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