Question

If the measures of opposite angles0/3
of a parallelogram are (60 - x) and
(3x - 4)º, then the measures of
angles of a parallelogram are ........
*
0 24°, 136°, 24°, 136
136°, 136°, 44°, 136°
84°, 96°, 84°, 96°
044°, 136°, 44", 136°​

Answer 1

Answer:

This implies that

x2+2ax=4x−4a−13

or

x2+2ax−4x+4a+13=0

or

x2+(2a−4)x+(4a+13)=0

Since the equation has just one solution instead of the usual two distinct solutions, then the two solutions must be same i.e. discriminant = 0.

Hence we get that

(2a−4)2=4⋅1⋅(4a+13)

or

4a2−16a+16=16a+52

or

4a2−32a−36=0

or

a2−8a−9=0

or

(a−9)(a+1)=0

So the values of a are −1 and 9.