Question

If the measures of the angles of a triangle are in proportion 2 : 3 : 5, then find the measures of all the angles of ΔABC.

Answer 1

BONJOUR,
❤ ❤ ❤ ❤
LET THE required angles be 2x, 3x, 5x
AS WE KNOW THAT SUM OF ANGLES IN A TRIANGLE IS 180 DEGREE SO THAT

2x+3x+5x =180
10x=180.
x= 180/10.
x =18


THEN

MEASURE OF ANGLES WILL BE:

1ST ANGLE = 36 degree
2nd ANGLE = 54 degree.
3rd ANGLE = 90 DEGREE

Answer 2

Hi ,

It is given that ,

In ∆ABC ,

<A : <B : <C = 2 : 3 : 5

Let <A = 2x ,

<B = 3x ,

<C = 5x

We know that ,

<A + <B + <C = 180°

[ angle sum property ]

2x + 3x + 5x = 180°

10x = 180

x = 180/10

x = 18

Therefore ,

<A = 2x = 2 × 18 = 36°

<B = 3x = 3 × 18 = 54°

<C = 5x = 5 × 18 = 90°

I hope this helps you.

: )