Question

If the measures of three angles of a triangle are (3x +3)°, (3x)° and (3x + 6)°, then find the value of x.

Answer 1

Step-by-step explanation:

Follow the steps in the picture.

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Answer 2

Given: Three angles of a triangle are (3x +3)°, (3x)°, and (3x + 6)°.

To find The value of x

Solution: On the basis of the angles are categorized into three types and are Acute angle, Obtuse angle, and Right-angled triangles.

• The triangle whose internal angles are less than 90° is referred to as the acute triangle.

• The triangle whose internal angles are more than 90° but less than 180° is referred to as the obtuse triangle.

• The triangle whose one angle is equal to 90° is referred to as the acute triangle.

Now we know that the sum of the three internal angles of a triangle is equal to 180°, so from above we get,

∴(3x +3)°+(3x)°+ (3x + 6)°=180°  [∵ (3x +3)°, (3x)°, (3x + 6)° are given angles]

⇒(3x+3x+3x)+3+6=180°

⇒9x+9=180°

⇒9x=(180-9)°

⇒9x=171°

⇒x=(171/9)°

⇒x=19°

Hence, 19° is the value of x.

The value of the first angle (3x +3)° is ((3×19)+3)° that is 60°.

The value of the second angle (3x)° is (3×19)°  that is 57°.

The value of the third angle (3x +6)° is ((3×19)+6)° that is 63°.