Question

If the median AD of a triangle ABC divides the angle ∠BAC in the ratio 1 : 2, then sinB/sinC is equal to

(a) 2 cos (A/3)

(b) (1/2) sec (A/3)

(c) (1/2) sin (A/3)

(d) 2 cosec (A/3)

Answer 1

Answer:

(d) 2 cosec (A/3)

Step-by-step explanation:

Hope it helps you

Answer 2

If the median AD of a triangle ABC divides the angle ∠BAC in the ratio 1 : 2, then sinB/sinC is equal to 2 cosec ( A / 3)

= d)2 cosec ( A / 3).

Hope it's helpful for you...