if the median height of 50 students of a class in the following frequency distribution is 144 cm find the missing frequency x and y
class interval frequency
125-130. 2
130-135. 4
135-140. x
140-145. y
145-150. 8
150-155. 9
155-160. 5
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Answer:
Height in cm
Number of students
cf
156
8
8
155
4
12
154
6
18
153
10
28
152
12
40
151
3
43
150
7
50
Total
50
Here N=50 Then
2
N
=
2
50
=25
N=50 is even, hence there will be two observations
2
n
and
2
n
+1i.e,25thand26th
Now, frequency greater than 25 is 28 and height for 28 is 153
Hence, median is 153.
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