Question

If the median of 12,13,16,X+2,X+4,28,30,32,is 23then find the value of X"?

Answer 1

Step-by-step explanation:

20

the median of

12,13,16,x+2,x+4,28,30,32 is 23

There are total 8 Term

=> Median = (4th term + 5th term)/2

x+2,x+4 lie between 16 and 30

=> 1st three term are 12 , 13 , 16

Last two term are 30 , 32

4th , 5th & 6th Term would be

x + 2 , x + 4 , 28 ( Not necessarily in this Sequence)

Case 1 : x + 4 ≥ 28

then 4th & 5th term would be x + 2 & 28

Median = (x + 2 + 28)/2 = 23

=> x + 30 = 46

=> x = 16

Then x + 4 = 20 < 28 so this case is not possible

Case 2 : x + 4 < 28

=> 4th & 5th Term would be

x+ 2 , x + 4

Median = (x + 2 + x + 4)/2 = 23

=> 2x + 6 = 46

=> 2x = 40

=> x = 20

Value of x = 20