Question

if the median of 46,64,88,40,x,76,35,91,56,32 and 91,find the value of x. answer is 58. plese solve this question.

Answer 1

x=19
46+64+88+40+76+35+91+56+32+91=619
answer=58
there are 11 numbers
therefore,
58*11=638

619+x=638
x=638-619
x=19

Answer 2

The value of x is 58.

Step-by-step explanation:

The given data set is

46, 64, 88, 40, x, 76, 35, 91, 56, 32, 91

Total number of observations = 11

11 is an odd number. So, median of the data set is

$(\dfrac{n+1}{2})\text{th term}=(\dfrac{11+1}{2})\text{th term}=6\text{th term}$

It is given that median of the given data is 58. It means when we arrange the data in ascending order then 6th term is 58.

In the given data set 58 is not available but an unknown number x is available. So, the value of x must be 58.

x = 58

On arranging the data in ascending order we get

(32, 35, 40, 46, 56), 58, (64, 76, 88, 91, 91)

Therefore, the value of x is 58.

#Learn more

Find the meadian and mode of the folloeing data and compare the results 7,4,12,0,5,7,3,10,8,8,12,5,7.

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