if the median of 46, 64 ,88 ,40 ,x,76, 35 ,91, 56, 32 and 91 is 58. find the value of x.
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Answered by
118
Hello Users.......
(46 + 64 + 88 + 40 + x + 76 + 35 + 91 + 56 + 32 + 91)/11 = 58.
(619+x)/11 = 58
x+619 = 638
x = 638 - 619
x = 19
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(46 + 64 + 88 + 40 + x + 76 + 35 + 91 + 56 + 32 + 91)/11 = 58.
(619+x)/11 = 58
x+619 = 638
x = 638 - 619
x = 19
Thank you.
Hope It Helps U :-)
ronaldo7777:
in my back of my book
answer book may be wrong
if u think i am wrong, so plz tell me how??
hello bro, I want to tell you something this is mean median what i found out. But how could find the value of x with this data
i can tell you the method how to find the median of given data
first arrangle the data in ascending order (n+1)/2th num will be the median
for odd num of data
it answer is 58
because when we find median for odd data n+1/2 term answer is 6 term =58 . We take x as 6 term so x =58 because 6term = 58
then we arrange the data in ascending order and put 58 in 6term so 58 is larger than 56 and smaller than 64
Answered by
10
Answer:
Step-by-step explanation:
46 + 64 + 88 + 40 + x + 76 + 35 + 91 + 56 + 32 + 91÷11 = 58.
So 619+x÷11 = 58
=x+619 = 638
=x = 638 - 619
=x = 19
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