If the median of a series exceeds the mean by 3, find by what number the mode exceeds its mean
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3( median)= 2(mean)+mode
let the men be 'x'
So,mean will be x+b
Then,according to the question
3( x+3)=2( x)+ mode
3x+9=2 x+mode
3x-2x+9-mode
Now,mode-mean
=x+9-x
=9
So,mode exceeds he mean by 9 answer
let the men be 'x'
So,mean will be x+b
Then,according to the question
3( x+3)=2( x)+ mode
3x+9=2 x+mode
3x-2x+9-mode
Now,mode-mean
=x+9-x
=9
So,mode exceeds he mean by 9 answer
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