Question

If the median of the data 35, 37, 40, 3m, 3m+4, 52, 57, 59 which is arranged in ascending order, is 47, find the value of m.

Answer 1

Step-by-step explanation:

Median value "M" is the data is

35 ,37 ,40 ,3 m ,3m+4 ,52 ,57 ,59 . Median is about the middle Number in the data.

Therefore here the median has the two numbers

they are 3 m,3m+4 .

If the place of median occupies the two numbers then solve both of them by the mean.(average)

Mean = sum of observations /total number

of observations

{ 3m+3m+4}/2 =47

6m +4/2 =47

6m+4 =47×2

6m+4= 94

6m=94-4

6m= 90

m= 90/6

m= 15

value of m is 15.

Therefore, value of 3m = 3×15=45.

value of 3m+4= 3×15+4= 49.

Therefore the median is 15.

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Answer 2

Answer:

45, 49

Step-by-step explanation:

Ascending order: 35, 37, 40, 3m, 3m+4, 52, 57, 59

47 =$\frac{( \frac{8}{2} )observation + ( \frac{8}{2} +1 )observation}{2}$

47 = $\frac{( 4 )observation + ( 5 )observation}{2}$

47 = $\frac{3m + 3m+4}{2}$

47 = $\frac{6m+4}{2}$

47 * 2 = 6m + 4

94 = 6m + 4

94 - 4 = 6m

90 = 6m

$\frac{90}{6}$  = m

15  = m

Therefore, 3m = 3 * 15 = 45

                  3m+4 = 3 * 15 +4 = 49