Question

if the median of the data x/3,x/2,x/4,x/9(x>0) is 5 then 'x' is​

Answer 1

Step-by-step explanation:

Given data :

$\frac{x}{3} \: \: \: \frac{x}{2} \: \: \: \frac{x}{4} \: \: \: \frac{x}{9}$

Rearranging the terms in ascending order,

$\frac{x}{9} \: \: \: \frac{x}{4} \: \: \: \frac{x}{3} \: \: \: \frac{x}{2}$

Now, Median =

$( \frac{ (\frac{4}{2}th \: term) \: + (\frac{4}{2} + 1)th \: term }{2} )$

$\frac{ {2}^{nd} term \: + {3}^{rd} term}{2}$

$\frac{ \frac{x}{4} + \frac{x}{3} }{2} = 5$

$\frac{3x + 4x}{12} = 10$

$7x = 120 \\ => x = \frac{120}{7} \\ x = 17 \frac{1}{7}$

Hence, the value of x = 17.14 (approx)