Question

if the median of the distribution id 1 find the possible values of x​

Answer 1

Answer:

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Step-by-step explanation:

C.I f c.f

0 - 10 5 5

10 - 20 x 5+x

20 - 30 20 25+x

30 - 40 14 39+x

40 - 50 y 39+x+y

50 - 60 8 47+x+y.

Total 68.

here, 47+x+y =68 _____ (1)

Given that, median = 27.

Hence the median class is 20 - 30.

∴l=20,

2

m

=

2

68

=34,c.f=5+x,h=10,f=20.

we know, median =l+

f

2

m

−c.f

×h

27=20+

20

34−(5+x)

×10

27=20+

2

34−5−x

⇒54=40+34−5−x.

⇒=69−x.

⇒x=69−54

⇒x=15

from (1), y = 68-47-15 = 6

Hence x = 15, y = 6