if the median of the series exceeds the mean by 3 find by what number the mode exceeds its mean
Answers
Answered by
65
Hey
Here is your answer,
3(median) = 2(mean) + mode
Let the mean be 'x'
So, median will be x + 3
Then, according to the question
3(x+3) = 2(x) + mode
3x + 9 = 2x + mode
3x - 2x + 9 - mode
x+9 = mode
Now, mode - mean
⇒ x+9 - x
= 9
So, mode exceeds the mean by 9
Hope it helps you!
Here is your answer,
3(median) = 2(mean) + mode
Let the mean be 'x'
So, median will be x + 3
Then, according to the question
3(x+3) = 2(x) + mode
3x + 9 = 2x + mode
3x - 2x + 9 - mode
x+9 = mode
Now, mode - mean
⇒ x+9 - x
= 9
So, mode exceeds the mean by 9
Hope it helps you!
Answered by
10
mode = mean+9
it is given that meadian = mean +3
by the formula, mode= 3 meadian -2mean
put first equation in place of meadian
mode = 3 ( mean+3) -2 mean
= 3 mean +9 -2 mean
therefore mode =mean +9
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