Question

If the median of the series exceeds the mean by 3 find the no. of mode exceeds its mean

Answer 1

Solution:-
3(median) = 2(mean) + mode
Let the mean be 'x'
So, median will be x + 3
Then, according to the question
3(x+3) = 2(x) + mode
3x + 9 = 2x + mode
3x - 2x + 9 - mode
x+9 = mode
Now, mode - mean
⇒ x+9 - x
= 9  
So, mode exceeds the mean by 9.  Answer

Answer 2

Answer:

3(median) = 2(mean) + mode

Let the mean be 'x'

So, median will be x + 3

Then, according to the question

3(x+3) = 2(x) + mode

3x + 9 = 2x + mode

3x - 2x + 9 - mode

x+9 = mode

Now, mode - mean

⇒ x+9 - x

= 9  

So, mode exceeds the mean by 9.

Step-by-step explanation: