If the mid-point of the line joining (3, 4) and (k, 7) is (x, y) and 2 x + 2 y + 1 = 0. find the value of k.
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Since (x,y) is the midpoint, using midpoint formula
![x = \frac{3 + k}{2} \: \: and \: \: y = \frac{4 + 7}{2} = \frac{11}{2} \\ given \: \: 2x + 2y + 1 = 0 \\ (3 + k) + 11 + 1 = 0 \\ k = - 15 x = \frac{3 + k}{2} \: \: and \: \: y = \frac{4 + 7}{2} = \frac{11}{2} \\ given \: \: 2x + 2y + 1 = 0 \\ (3 + k) + 11 + 1 = 0 \\ k = - 15](https://tex.z-dn.net/?f=x+%3D++%5Cfrac%7B3+%2B+k%7D%7B2%7D++%5C%3A++%5C%3A+and+%5C%3A++%5C%3A+y+%3D++%5Cfrac%7B4+%2B+7%7D%7B2%7D++%3D++%5Cfrac%7B11%7D%7B2%7D++%5C%5C+given+%5C%3A++%5C%3A+2x+%2B+2y+%2B+1+%3D+0+%5C%5C+%283+%2B+k%29+%2B+11+%2B+1+%3D+0+%5C%5C+k+%3D++-+15)
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