Question

If the mid point (x,y) of the line joining (3,4) and (p,7) lies on 2x+2y+1=0, then what will be the value of p?

Answer 1

hey mate!

here is your answer:


hope it helped ^_^

Answer 2

★ Method of Solution : ✯

Given : If the mid point (x,y) of the line joining (3,4) and (p,7) lies on 2x+2y+1=0,

Let A and B vertices of their points!

Here, A = (3,4). and B = (P,7)

Now, According to the Question's Statement!

Statement : If the mid point (x,y) of the line joining (3,4) and (p,7) lies on 2x+2y+1=0,

We know that Midpoint Formula of Coordinate Geometry!

Midpoint Formula : { x1 + x2 / 2 , Y1 + Y2/2 }

Substituting the obtained value on Formula!

Midpoint Formula : { x1 + x2 / 2 , Y1 + Y2/2 }

( x , y ) = (3+ p / 2 ) , ( 4 + 7 / 2)

x = 3 + p / 2 , or y = ( 4+7/2)

•°• x = 3 + p/ 2 or y = 11 /2

Here, Value of x and y are (3+p) and 11 respectively!

Equation : 2x+2y+1=0,

→ 2 ( 3 + p/2 ) + 2 (11/2) + 1 = 0

→ 3 + p + 11 + 1 = 0

→ p + 3 + 12 = 0

→ p + 15 = 0

→ p = - 15

•°• p = -15

Hence, Required Value of p is (-15).