Math, asked by lavanyasingh3386, 10 months ago

If the midpoint of line AB is (3,4) and abscissa of A is equal to ordinary of B then difference between the ordinate A and abscissa B is?

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Answers

Answered by knani2830
5

Answer:

Step-by-step explanation:

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Answered by bhuvna789456
0

The difference between the ordinate of A and abscissa of B is 2

Step-by-step explanation:

Let the abscissa of A be x and by the given condition ordinate of B = abscissa of A, therefore ordinate of B is x.

Let ordinate of A be y and abscissa of B be z.

Therefore we can write the points as : A (x,y) and B (z,x)

Given that midpoint of AB is (3,4)

By the midpoint formula,

\frac{x+z}{2} = 3

x + z = 6 ---- (i)

And also , \frac{y + x}{2} = 4

y + x = 8 ---- (ii)

Subtracting (i) from (ii)

y + x - (x + z) = 8 - 6

y + x - x - z = 8 - 6

y - z = 2

Therefore the difference between the ordinate of A and abscissa of B is 2

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