if the midpoint of the line segment joining the points p(6,b-2) and Q(-2,4) is (2,-3) find the value of b?.
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According to question
P= (6,b-2)
Q=(-2,4)
and Midpoint of PQ is
(2,-3)
therefore x=2. and y=-3
Midpoint y = y1 +y2/2
-3=b-2+4/2
-6=b-2+4
-6-4=b-2
-10=b-2
-8=b
Ans=b=-8
P= (6,b-2)
Q=(-2,4)
and Midpoint of PQ is
(2,-3)
therefore x=2. and y=-3
Midpoint y = y1 +y2/2
-3=b-2+4/2
-6=b-2+4
-6-4=b-2
-10=b-2
-8=b
Ans=b=-8
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