if the midpoints of the longest side of the triangle formed by the line 4x+3y= 12 , x=0 , y=0 is ( 3sinalpha, 4cosBita), then cot(3alpha-bita) is
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Equation :- 4x+3y=12
When the graph cuts x-axis, y coordinate becomes zero.
⇒4x+3(0)=12
⇒4x=12
⇒x=3
Similarly, when the graph cuts the y-axis, x coordinate is zero.
⇒4(0)+3y=12
⇒3y=12
⇒y=4
If OA=3units
OB=4units
By Pythagoras theorem
(AB)
2
=(OA)
2
+(OB)
2
=(3)
2
+(4)
2
=9+16
=25
=
25
⇒AB=5units
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