If the midpoints of the sides bc ca and ab of triangle abc are 3,-3;3,-1;1,1 respectively,then the vertices of a,b,c are
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Answer:
(5,-5) (1,-1) (1,3)
Step-by-step explanation:
let points are
a,b
c,d
d,e
then a+e+c=7
so c=5
a=1
e=1
do same for b,d,and e
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