If the midsegment of a triangle is 5x plus 3 and the base is 27 what is the measure of the midsegment?
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Yes they are, no matter what way, what size and you put them all together it will come out as a triangle For an interesting type of triangle that has all its' angles at 90 degrees take an orange or tennis ball and draw a triangle on it joining up all three axies. Show it to your teacher, they will be impressed. Then tell you friends to draw you a triangle with ALL three angles at 90 degrees, don't tell them about the ball until you show them.
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Answer:
13.5 units
Explanation:
By mid point theorem
Midsegment is always half of the base of the triangle.
Let ABC be a triangle where D and E are the mid points of sides AB and AC respectively. BC is the base of the triangle.
Therefore DE is the midsegment.
DE = 5x + 3
BC = 27
Hence,
DE = 1/2 BC
5x + 3 = 1/2 *27
5x + 3 = 13.5
5x = 10.5
x = 2.1
Therefore
DE = 5*(2.1) + 3 =10.5 + 3
DE = 13.5 units
Thus the length of midsegment is 13.5 units.
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