Question

If the mode of a series exceeds it's mean by 12,then mode exceeds the median by what?

Answer 1

let mean = x
then mode = x+12
now, 3 median = mode + 2 mean
⇒ 3 median = x + 12 + 2x
⇒ 3 median = 3x + 12
⇒ 3 median = 3(x + 4)
⇒ median = x + 4
now mode - median = (x + 12) - (x + 4)
so mode - median = x + 12 - x - 4
⇒ mode - median = 8
Hence mode exceeds median by 8.

Answer 2

Answer:

Hey guys i am Ritupriya

Suppose mean be x

So, mode will be x + 12

Then 3 median will be:

= x + 12+ 2x

= 3x + 12

or 3 (x+4)

So, 1 median or median will be:

(x+4)

Here, Mode - Median 

= (x+12) - (x+4)

= x + 12 - x + 4

= 8

∴ The mode exceeds the median by 8.

Hope you got it!!!