Question

If the molal elevation constant of the solvent is 0.5 K kg mol-1, then what will be elevation in boiling point for 0.1m solution

Answer 1

Answer:

.05

Explanation:

We know that elevation in bp is equal to kb× m= .1×.5= .05

Answer 2

If the molal elevation constant of the solvent is 0.5 K kg mol-1, then the elevation in boiling point for 0.1m solution will be 0.05K

According to the molal elevation constant formula,

ΔTb = Kb × m

where ΔTb is the elevation in boiling point

Kb is the molal elevation constant = 0.5 K kg mol^-1.

m is the molality of the solution = 0.1 m

Putting the values in the above equation, we get

ΔTb = 0.5 × 0.1 = 0.05K

Thus, the elevation in boiling point will be = ΔTb = 0.05K