Question

If the molar concentration of Ag+ is 2m. Calculate the potential of electrode Ag/Ag+ at 25°C. Given that E° for Ag+/Ag =0.8V​

Answer 1

Given: molar concentration of Ag+ is 2M

E° for Ag+/Ag =0.8V​

To find: the potential of electrode Ag/Ag+ at 25°C

Explanation:

According to Nernst Equation,

$E_{Ag/Ag^{+} }= E_{cell}- \frac{2.303RT}{nF} log \frac{1}{[M^{n+} ]}$

$E_{cell}=0.8 V\\n=2\\F=96500 C/mol$

$R=8.314 J/K mol$

$T=398 K$

$Ag^{+}= 2 M$

On substituting the above values in the equation, we get,

$E_{Ag/Ag^{+} }= 0.8-\frac{2.303\times 8.314\times 298}{96500} log\frac{1}{2}$

$E_{Ag/Ag^{+} }= 0.8 - [0.05912\times(-0.301)]$

$E_{Ag/Ag^{+} }= 0.8+0.017= 0.817 V$

Hence, the potential of given electrode is 0.817 V