If the molar conductance of 0.04 M solution of weak monobasic acid is 10 S cm² mol-1 and at infinite dilution is 500 S cm² mol-1 then the dissociation constant of the acid will be
a. 8 x 10-4
b. 1.6 x 10-5
c. 2.4 x 10-6
d. 4.0 × 10-4
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Answer:
) Molar conductance Λ
m
= CK×1000
= 0.011.65×10 −4 ×1000
=16.5 ohm −1 cm 2 mol −1
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