If the mole fraction of benzene in a particular benzene-toluene solution is 0.64, what is the mole fraction of benzene in the vapor phase in equilibrium with that solution? A) 0.24 B) 0.50 C) 0.64 D) 0.78 E) 0.87
Answers
Answered by
0
Explanation:
Correct option is
A
237
The partial pressure of toluene in the vapour phase is
P
T
=P
T
0
X
T
=37 torr×0.5=18.5 torr.
Here, P
T
0
is the vapour pressure of pure toluene and X
T
is the mole fraction of toluene in the liquid phase.
The partial pressure of benzene in the vapour phase is
P
B
=P
B
0
X
B
=119 torr×0.5=59.5 torr.
Here, P
B
0
is the vapour pressure of pure benzene and X
B
is the mole fraction of benzene in the liquid phase.
The total pressure is P
T
+P
B
=18.5 torr+59.5 torr=78 torr.
The mole fraction of toluene in the vapour phase is Y
T
.
It is given by the expression Y
T
=
totalpressure
P
T
=
78
18.5
=0.237.
Hence, the mole fraction of toluene in the vapour phase is 0.237.
Hence the correct answer is 237
Similar questions