If the molecular weight of BA mno4 taken twice is M when the equivalent weight of BA mno4 taken twice in acidic medium is
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Ba(MnO4)2⟶Ba2++2MnO4−
↓
2Mn2+
Ba being most electro positive element does not get reduced to Ba, thus only MnO4− gets reduced to Mn2+ as it always does in acidic medium.
And since compound has 2 atoms of Mn in it so, its' n factor is given by,
(Change in oxidation number per atom)×(Number of atoms per molecule or formula unit of the given reagent)
=5×2=10
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