If the moment of inertia of uniform circular ring of
mass M and radius R about an axis through its
centre and perpendicular to its plane is I. Then
moment of inertia of a uniform semi-circular ring
of mass M and radius R about axis through its
centre and perpendicular to its plane will be
(the answer is I but I need an explanation.)
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0
Answer:
don't know bro..................
Answered by
1
Explanation:
semicircular wire.
moment of inertial about a point at distance r is given by:
dI=dmr
2
to find total moment of inertia, integrate both sides
∫dI=r
2
∫dm
∫dm=M, total mass of body.
I=Mr
2
.
so The moment of inertia of a uniform semicircular wire of mass M and radius r about a line perpendicular to the plane of the wire and passing through its centre is Mr
2
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