Question

if the momentum is increased by 10% then its kinetic energy will increase by how much percent

Answer 1

P' = 10%p + p
P' = 10÷100p+p
P' = 0.1p+p
P' = 1.1p


K.e' = p2 ÷ 2m
K.e' = (1.1p)2 ÷ 2m
K.e' = 1.21 p2 ÷ 2m
K.e' = 1.21 k.e





k.e = k.e' - k.e ÷ k.e
K.e = 1.21 - k.e ÷ k.k.e
K.e = 0.21 ke ÷ ke
K.e = 0.21

% of k.e = 0.21 ×100
% of k.k.e = 21%



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Answer 2

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