If the momentum is increased by 20% then the kinetic energy will be increased by how much percent
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Kinetic energy and momentum are related as
K = p²/(2m)
For an object of mass m
K ∝ p²
K₂/K₁ = (p₂/p₁)² ....(1)
Let’s say initial kinetic energy and momentum be 100% each
Then, equation (1) will become
(K₂ / 100%) = (120% / 100%)²
K₂ / 100% = 1.44
K₂ = 144%
Increase in kinetic energy = 144% - 100% = 44%
∴ Kinetic energy is increased by 44%
K = p²/(2m)
For an object of mass m
K ∝ p²
K₂/K₁ = (p₂/p₁)² ....(1)
Let’s say initial kinetic energy and momentum be 100% each
Then, equation (1) will become
(K₂ / 100%) = (120% / 100%)²
K₂ / 100% = 1.44
K₂ = 144%
Increase in kinetic energy = 144% - 100% = 44%
∴ Kinetic energy is increased by 44%
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