If The Momentum Is Increased By 50% Then Kinetic Energy changes by
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Original momentum = mv
New momentum = mv +( (50/100) mv)
= mv +(mv/2)
=3mv/2
Mass is fixed . It cannot change.So velocity is the reason for it's increase.
Let new velocity = v'
New momentum= mv' = 3mv/2
v'=3v/2 (mass get cancelled).
New kinetic energy = m(v')²/2 = m× (3/2 v)² /2
=9/8 × mv²
Original kinetic energy = mv²/2
∴ the percentage increased = (9/8 - 1/2) ×100
=5/8 × 100
= 62.5%
I hope my answer is helpful to u.
New momentum = mv +( (50/100) mv)
= mv +(mv/2)
=3mv/2
Mass is fixed . It cannot change.So velocity is the reason for it's increase.
Let new velocity = v'
New momentum= mv' = 3mv/2
v'=3v/2 (mass get cancelled).
New kinetic energy = m(v')²/2 = m× (3/2 v)² /2
=9/8 × mv²
Original kinetic energy = mv²/2
∴ the percentage increased = (9/8 - 1/2) ×100
=5/8 × 100
= 62.5%
I hope my answer is helpful to u.
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