Physics, asked by lahore778, 1 year ago

if the momentum of a body decreases by 20% the percentage decrease in kinetic energy will be

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Answered by Anonymous

here is ur answer hope it helps u

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Answered by Vaiarathe

KE = p^2/2m

Momentum decreases by 20%
So p' = 0.8p

KE' = p'^2/2m

KE' = (0.8p)^2/2m

KE' = 0.64 p^2/2m

KE' = 0.64 KE

Decrease in KE = (1-0.64)KE = 0.36

% decrease in KE = 36%

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