If the momentum of a body decreases by30% ,then kinetic energy decreases by
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0
Answer:
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51%
Explanation:
Let the Momentum be = p
Initial Kinetic Energy (KE) = p²/2m = 0.5p²/m
The momentum is said to be decreased by 30%
Therefore,
New Momentum =
= p−p×30% = 0.7p
New Kinetic Energy =
=> (0.7p)²/2m = 0.49p²/2m = 0.245p²/m
Net decrease or difference in Kinetic energy
= (0.5p²/m)−(0.245p²/m)
= 0.255p²/m
Hence, Percentage (%) decrease in Kinetic Energy
= {(Decrease or Difference In KE) ÷ (Initial KE)} × 100
= {(0.255p²/m) ÷ (0.5p²/m)} × 100
= 51% decrease in the Initial Kinetic Energy.
Hope it helps. :)
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