if the momentum of a body is decreased by 30% by keeping mass constant what will be percentage change in kinetic energy. explain in the full process by solving it.
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Answer:
k.e = 1/2 mvsq
p= m.v
in a k.e multiply denominator and numerator by m
= 1/2 msq vs q/m
e= 1/2 psq/m
considering mass to be constant if p is decreased by 30% then
new p = p -30/100 p = 0.7p
and
new k.e = (0.7p)/2m
we know that
k.e = (1/2musq)
new k.e = 0.49psq / 2m
% age decrease in k.e = (k.e new k.e) / k. e
there for decrease in k.e = 51%
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