If the momentum of a body is decreased by 50% then the kinetic energy decreases by plz give explanation.
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If momentum of a body increases by 50% by what % its K.E. change?
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Let the initial momentum be Pi =P
Final momentum PP =1.5P
Initial kinetic energy K.E i = 2mp 2
Final kinetic energy K.Ef= 2mp f2f = 2m(1.5P) 2
=2.25K.E i
Percentage increase in kinetic energy
K.E f−K.E i/K.E i×100= 2.25−1/1 ×100=125 %
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