if the momentum of a body is increased by 100% then the kinetic energy of body is increased by
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KE will increase by 300% as depicted in image. If the momentum increases by 100% , then the p increases to 2p. When momentum of a body increases by 100% then its kinetic energy will increase by 300%
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K =p^2/2m
100% of P= 100/100×p=p
final momentum=P+P=2P
K` =(2P) ^2/2m
=4p^2/2m =4K
% increase in K. E= 4K-k/K×100
=300%
100% of P= 100/100×p=p
final momentum=P+P=2P
K` =(2P) ^2/2m
=4p^2/2m =4K
% increase in K. E= 4K-k/K×100
=300%
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