Question

If the momentum of a body is increased by 50% calculate percentage change in its kinetic energy

Answer 1

Suppose the original momentum of the body to be ‘p’ and a 50% increase leads to amomentum of p+(50/100)p=1.5p

The relation between momentum ‘p’ and kinetic energy ‘k’ is p^2=2km (m is mass of object) hence k=(p^2)/2m

New kinetc energy

k' = ((1.5p)^2)/2m ( as new p is 1.5p)

k'=2.25*((p^2)/2m) =2.25*k

So, kinetic energy increased by 125%