Question

If the momentum of a body is increased by 50%, its K.E
will increase by​

Answer 1

Answer:

p- √2mke

by this equation ke will increase by 100 percent

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Answer 2

formula for kinetic energy is :-

K = 1/2 × mv²

multiply and divide RHS by m.

K = 1/2 × m²v² × 1/m

K = 1/2 × p² × 1/m (Here, p is momentum p = mv)

=> p² = 2mK

=> p = √(2mk)

using this relation we can tell p is directly proportional to √K

50% increase means increment by 1/2 times of orginal value

So, if momentum is increased by 1/2 times, the increase in kinetic energy by above relation will be 1/4, which is an increment of 125%.

So, K.E. is increased by 125%.