If the momentum of a body is increased by 50% then what will be the percentage increase in the kinetic energy of the body
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Suppose the original momentum of the body to be ‘p’ and a 50% increase leads to amomentum of p+(50/100)p=1.5p
The relation between momentum ‘p’ and kinetic energy ‘k’ is p^2=2km (m is mass of object) hence k=(p^2)/2m
New kinetc energy
k' = ((1.5p)^2)/2m ( as new p is 1.5p)
k'=2.25*((p^2)/2m) =2.25*k
So, kinetic energy increased by 125%
Hope this helps....
nancyjain18:
thanks
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