If the momentum of a certain body is increased by 50% then increase in the kinetic energy of the body will be
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p=√2mK
p2=1.5p
p/p2=√k1/√k2
p/1.5p=√(k1/k2)
4/9=k1/k2
k2=9k1/4
kinetic energy becomes 9/4 times
p2=1.5p
p/p2=√k1/√k2
p/1.5p=√(k1/k2)
4/9=k1/k2
k2=9k1/4
kinetic energy becomes 9/4 times
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