Question

If the momentum of an electron moving with a velocity 0.9 c is increased by 1%, then the increase in its energy is:

Answer 1

Hey Dear,

◆ Answer -

Increase in kinetic energy = 2 %

● Explaination -

Kinetic energy of an electron is given by formula -

KE = 1/2 mv²

KE = p²/2m

As m (mass of e-) is always constant, 1/2m is taken as constant.

KE = k.p²

Relative increase in energy of the electron is -

∆KE/KE = 2∆p/p

∆KE/KE = 2 × 1%

∆KE/KE = 2 %

Hence, increase in kinetic energy will be 2 %.

Hope this helps you...

Answer 2

Explanation:

here is the answer for it we come to know its independent of the given velocity...hence answer is .0.99%