If the momentum of an object is increased by 10pecent then its kinetic energy will increase by?
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Answered by
1
Answer:
option 2
kinetic energy increases by 21%
kinetic energy(K)=(momentum)^2/2*mass
given momentum is increased by 10%
so let the new momentum be 1.1p=p1
let new kinetic energy=k1
k1/k=(p1)^2-(p)/p*100=1.21p^2-p^2/p^2*100
=.21p^2/p^2*100
=21%
Explanation: hope it helps...!!!
Answered by
0
Answer:
i guess it is 20%
Explanation:
p is directly proportional to v as mass in this whole scenario would remain same
k is directly proportional to v^2 as 1/2*m would remain constant
if v is increased by 10% then v^2 will increase by 20 %
as v^2 would be 10^2
and in directly proportional sign u multiply 10 by 2 to get % change
therefore 10*2 would be 20
hope this helps
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