Question

If the momentum of certain body is increased by 50% then increase in the kinetic energy of the body will be

Answer 1

momentum = mass*velocity

p = mv

let the momentum be mv

so if it increased by 50% then

=> 50%ofmv + mv

=> 3/2mv

& kinetic energy intial = 1/2mv²

now new velocity (v2) = 3/2v

hence new kinetic energy = 1/2mv2²

=>1/2m*(3/2v)²

now % increased in kinetic energy = (1/2m*(3/2v)²/1/2mv²)*100

=>225%