Question

If the momentum of the body increases by 10% by what percent its kinetic energy increases

Answer 1

☆☆ AS-SALAMU-ALYKUM ☆☆

●●●●●●●●●●●●●●●●●●●●

GIVEN DATA

10% INCREASE IN MOMENTUM

RELATION BETWEEN KINETIC ENERGY AND MOMENTUM IS :-
▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪

KINETIC ENERGY = MOMENTUM ^2÷2m

K.E = P^2÷2M _____________________1

NEW MOMENTUM :-
▪▪▪▪▪▪▪▪▪▪▪▪▪

P + 10 %P

P+10÷100P

P+ 0.1P

P'=1.1P

NEW KINETIC ENERGY IS :-
▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪

K.E' = P^2÷ 2M

K.E' = (1.1P)^2 ÷2M ------------------------------------2

DIVIDE EQUATION 2 BY EQUATION 1

K.E' ÷K.E=(1.1P)^2÷2M / P^2÷2M

OR

K.E'÷K.E = (1.1P)^2÷2M × 2M ÷P^2

K.E'÷K.E = (1.1 )^2

K.E'÷K.E = 2.2

K.E'= 2.2K.E

●●●●●●●●●●●●●●●●●●●●●


$<marquee>$ INSHALLAH IT WILL HELP U

HAVE A NICE DAY☺☺☺

Answer 2

since , we know that ,

kinetic energy (K.E) = 1 / 2 mv^2





_______________________________
if the momentum of the body increased by 10 %then obviously its velocity will be increased .
_______________________________




let increase in momentum 'm ' = 10%





and increase in its velocity ' v' = 10 %




increase in kinetic energy





= m + v + ( mv/ 100 )




= 10 + 10 + ( 10×10 /100 )



= 20 + ( 100 /100 )





= 20 + 1 = 21 %


therefore ,



kinetic energy will be increased by 21% .

_______________________________
Your Answer : 21 %
_______________________________