If the momentum ofa body is increased by 50%, its kinetic energy will increase by
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Answered by
3
Answer:
Let, the initial momentum of the body is p.
The change in momentum is
p
′
=p+
100
50
p
p
′
=p+0.5p=1.5p
The kinetic energy of the body is
E=
2
1
mv
2
E=
2m
(mv)
2
=
2m
p
2
.......(1)
Since, p=mv
where m is the mass of the body
Now, the kinetic energy of the body due to changed momentum is
E
′
=
2m
(mv
′
)
2
=
2m
p
′2
..........(2)(since, p
′
=mv
′
)
From (1) and (2)
E
E
′
=
p
2
p
′2
E
E
′
=
p
2
(1.5p)
2
E
E
′
=2.25
E
′
=2.25E
The percent change in kinetic energy is
E
E
′
−E
×100=
E
2.25E−E
×100
⇒1.25×100=125%
Answered by
2
Answer:
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