If the momentumof body is incresae by 10%what is kinetic energy of that body
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Let the initial mass of the body be m and its velocity be v.
Initial momentum of the body = mv
Initial KE = mv^2/2
If the momentum increases by 10%, new momentum = mv + 10% of mv
= mv + 10/100mv
= mv + mv/10
=11mv/10
=m(11v/10)
New velocity = 11v/10
Increase in velocity = v/10
New KE = m(11v/10)^2/2
= 121/100mv^2/2
Increase in KE = 21%
Initial momentum of the body = mv
Initial KE = mv^2/2
If the momentum increases by 10%, new momentum = mv + 10% of mv
= mv + 10/100mv
= mv + mv/10
=11mv/10
=m(11v/10)
New velocity = 11v/10
Increase in velocity = v/10
New KE = m(11v/10)^2/2
= 121/100mv^2/2
Increase in KE = 21%
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