If the monthly salary of a person is increased by 8/3% he gets 72 rupees more his monthly salary is?
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Let monthly salary be rs.x
Increase percent=8/3%
Increase in amount=rs.72
Increased salary=rs.(x+8/3% of x)
So, according to the problem,
rs.x+8/3% of rs.x=rs.(x+72)
or, x+(8/3÷100×x)=x+72
or, x+(8/3×1/100×x)=x+72
or, x+2x/75=x+72
or, (75x+2x)/75=x+72
or, 77x/75=x+72
or, 75(x+72)=77x
or, 75x+(75×72)=77x
or, 77x-75x=75×72
or, 2x=75×72
or, x=(75×72)/2=2700
or, rs.x=rs.2700
Ans. His original monthly salary is rs.2700.
Increase percent=8/3%
Increase in amount=rs.72
Increased salary=rs.(x+8/3% of x)
So, according to the problem,
rs.x+8/3% of rs.x=rs.(x+72)
or, x+(8/3÷100×x)=x+72
or, x+(8/3×1/100×x)=x+72
or, x+2x/75=x+72
or, (75x+2x)/75=x+72
or, 77x/75=x+72
or, 75(x+72)=77x
or, 75x+(75×72)=77x
or, 77x-75x=75×72
or, 2x=75×72
or, x=(75×72)/2=2700
or, rs.x=rs.2700
Ans. His original monthly salary is rs.2700.
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